0.00222x(0.0188-x)=4x^2

Solution for 0.00222x(0.0188-x)=4x^2 equation:

0.00222x(0.0188-x)=4x^2

We move all terms to the left:

0.00222x(0.0188-x)-(4x^2)=0

determiningTheFunctionDomain
-4x^2+0.00222x(0.0188-x)=0

We add all the numbers together, and all the variables

-4x^2+0.00222x(-1x+0.0188)=0

We multiply parentheses

-4x^2+0x^2+0x=0

We add all the numbers together, and all the variables

-3x^2+x=0

a = -3; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-3)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-3}=\frac{-2}{-6}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-3}=\frac{0}{-6}
=0
$